Topological Sorting

Question:

http://www.lintcode.com/en/problem/topological-sorting/
Given an directed graph, a topological order of the graph nodes is defined as follow:
For each directed edge A -> B in graph, A must before B in the order list.
The first node in the order can be any node in the graph with no nodes direct to it.
Find any topological order for the given graph.

Answer:

class Solution {
public:
    /*
     * @param ratings: Children's ratings
     * @return: the minimum candies you must give
     */
    int candy(vector<int> &ratings) {
        // write your code here
        vector<int> candys(ratings.size(), 1);
        for (int i = 0; i < ratings.size() - 1; i++) {
            if (ratings[i+1] > ratings[i])
                candys[i+1] = candys[i] + 1;
        }
        for (int i = ratings.size() - 1; i > 0; i--) {
            if (ratings[i-1] > ratings[i])
                candys[i-1] = max(candys[i] + 1, candys[i-1]);
        }
        int count = 0;
        for (auto i : candys)
            count += i;
        return count;
    }
};

❤️ Support This Blog

---

If this post helped you, you can support my writing with a small donation. Thank you for reading.

---

Coffee ☕ Thanks 🙏 Extra Support ❤️